Send JSON and parse in PHP

Hi !

I'm searching for days now and i can't find the mistake, i send my json :

var xhr = Ti.Network.createHTTPClient();
xhr.open("POST", "http://****.php");
xhr.setRequestHeader('Content-Type', 'application/json; charset=utf-8');
 
var postData = {
    object: { child1:'value', child2:'value' }
}
xhr.send(JSON.stringify(postData));

And in my php, i tried :

$data = json_decode(stripslashes($_POST['postData']), true);

$data = json_decode(stripslashes($_POST['object']), true);

$data = json_decode($_POST['postData']);

$data = json_decode($_POST['object']);

But $data is always null, where did i fail ?

TY

Problem 1: don't stringify your POST data, just send it directly, like this:

var xhr = Ti.Network.createHTTPClient();
xhr.open("POST", "http://****.php");
xhr.setRequestHeader('Content-Type', 'application/json; charset=utf-8');
 
var postData = {
    object: { child1:'value', child2:'value' }
}
xhr.send(postData);

Problem 2: the server won't see anything called 'postData'. That's just a variable name in your javascript. The server script's $_POST data will look like this:

object: {
    child1 = value;
    child2 = value;
}

So to use it, you would just do this:

$child1 = $_POST['child1'];
$child2 = $_POST['child2'];

Jason is right, also var_dump($_POST); is your choice to check the passed data before trying to access it

TY Jason, Shannon and Anthony, this was nice. Sorry for late answer but i wanted to test with and without json and i finally used Shannon solution : $data = json_decode($_POST['myData'], true);

The second parameter return this output instead of Jason output :

array(1) {
  ["objectiflist"]=>
  array(2) {
    [0]=>
    array(2) {
      ["id"]=>
      int(1)
      ["label"]=>
      string(3) "one"
    }
    [1]=>
    array(2) {
      ["id"]=>
      int(2)
      ["label"]=>
      string(3) "two"
    }
  }
}

And then, to get my data : $data['objectiflist'][0]['id'];

TY everybody for your help ;)

In my PHP (5.4) page I use the function file_get_contents to read post data, otherwise PHP don't see nothing.

$aRequest = json_decode(file_get_contents('php://input'), true);